 | 1801 - Страниц: 446
...root. 16. Involve the whole root to the given power, and subtract it from the given number as before. 7. Bring down the first figure of the next period to the remainder for a new dividend, to whjch find a new divisor, arid so on, till the whole be finished. PXAMPJ.ES j. What is the cube root... | |
 | Jeremiah Paul - 1801 - Страниц: 238
...4. Involve thr whole root to the given power, and subtract it from the two first periods. Bringdown the first figure of the next period to the remainder for a new di>idend, to which find a new divisor as before ; and so proceed till the whole be finished. The roots... | |
 | Nicolas Pike - 1802 - Страниц: 350
...whole root to the given power, and fubtraft it from the given number as before. 7. Bring down the firft figure of the next period to the remainder for a new dividend, to which find a new divifor, as before, and, in like manner, proceed till the whole be fiaiihed. EXAMPLES. •» i. What... | |
 | Nicolas Pike - 1807 - Страниц: 370
...root to the given power, and fabtraft it from, the given number as before. 7. Bring down the firft figure of the next period to the remainder for a new dividend, to which find a new divifor, as before, and, in like manner, proceed till the whole be finilhcd. EXAMPLES. >. ' What is... | |
 | Nicolas Pike - 1808 - Страниц: 470
...Involve the whole root to the given power, and subtract it from the fivfn number, as before. 7- Brinjr down the first figure of the next period to the remainder...dividend, to which find a new divisor, as before, and, m like manner, proceed till the whole be finished. EXAMPLES. ' The eitradHng of roots of very high... | |
 | Samuel Webber - 1808 - Страниц: 466
...root. 6. Involve the whole root to the given power, and subtract it from the given number as before. 7. Bring down the first figure of the next period...remainder for a new dividend, to which find a new divisor, and so on, tiU the whole be finished. EXAMPLES. 1. What is the cube root of 53157376 ? 53157376(376... | |
 | 1811 - Страниц: 210
...Involve the whole ascertained root to the given power, and subtract it from the first and second periods. Bring down the first figure of the next period to...dividend ; to which, find a new divisor, as before ; and so proceed. . . Note. — The roots of the 4th, 6th, 8th, 9th and 12th powers, may be obtained more... | |
 | Samuel Webber - 1812 - Страниц: 260
...figure of the next period to th« remainder for a new dividend, to which find a new divisor, and so on, till the whole be finished! EXAMPLES. 1. What is the cube root of 53157376 ? 53157376(376 27=3 3 32X3=27)261 dividend. 50653=373 3*X3±=4107)25043 second dividend. 53157376... | |
 | Nathan Daboll - 1813 - Страниц: 244
...number •is you have found figures in the root. 7. Bring down the first figure of the next, prrio.l to the remainder for a new dividend, to which find a new divisor aa before, and in like manner proceed till the whole be finished. NOTE. — When the number to he subtracted... | |
 | Nathan Daboll - 1815 - Страниц: 250
...subtract it (always) from as many periods of the given number. as you have found figures in the root. 7. Bring down the first figure of the next period...remainder for a new dividend, to which find a new divigor, as before, and in like manner proceed- till the whole be finished. NOTE. — When the number... | |
| |
... 7. Bring down the first figure of the next period to the remainder for a new dividend, to which find a new divisor as before, and in like manner proceed till the whole be finished. 
